Would anyone like to chime in. I recently made an MOT spot welder for 18650 nickel strips. I can reliably weld 0.2mm nickel. Although I do need a slit if I’m doing nickel <–> nickel (stacking for more amps).

My main problem here is that I had to use 2 parallel transformers since I can’t source a single more powerful one e.g. 1500w

The current ones are around 700 and 900 watts. Together, they manage around 20 amps from the wall 220v, that’s about north of 4kW, so I’m guessing 2000 amps at 2 volts in theory.

In practice, I’m probably closer to 1000 amps due to heat and smaller electrode tips near the end for the spots.

Any ideas if raising my voltage to 4 volts would help with welds? I might also switch out my SSR since it seems to be sagging on that end. I measure more amps on the free directly connected cable from time to time, versus the one coming from the SSR.

Edit: The cables on the secondary windings are 16mm2 or around 6AWG. I’m confident they can handle the load since I can’t really feel any heat in them. They barely heat up after 5 seconds of a constant short. I’m doing mostly 50-60ms pulses for the welds.

  • jetA
    link
    fedilink
    English
    arrow-up
    3
    ·
    1 year ago

    All of my electronics is rusty, so my observations are as a curious spectator but not with any authority

    By your own math, you’re pushing 4kW through a system only rated for 1.8kW (2 900W transformers). Since your pulsing and it’s not consistent duty cycle it’s probably okay. But I would worry about it when you’re talking about doubling your power draw.

    From a theoretical position, doubling your voltage should double your power, so that put you at 8 kW instantaneous draw). What’s your 220 volt input circuit rated for?

    Have you thought about charging capacitors and then drawing from those capacitors for the instantaneous load?

    Assuming you have the power capacity for your individual welding loads, I don’t see why double the voltage wouldn’t be better, as long as there’s not delicate electronic circuitry that could be damaged from an inrush voltage you should be golden

    • roterabe@discuss.tchncs.deOP
      link
      fedilink
      English
      arrow-up
      2
      ·
      1 year ago

      Hmm, maybe I should have clarified. You would be correct if I was talking about doubling the overall power. I meant simply adding another turn to my secondary coils so as to raise the voltage and lower the amps a bit or to connect the 2 transformers in series.

      Caps seem like a decent idea actually. The house is rated for something north of 40 amps so I should be fine for a ms load.

      • jetA
        link
        fedilink
        English
        arrow-up
        1
        ·
        1 year ago

        I did some basic googling, and there’s a bunch of different spot welding materials amperage and voltage tables. Ideally you’d want to use the minimum amount of amperage, and voltage for the material you’re welding, it’s thickness, and the attenuation size of the rest of the material.

        Those look up tables, at least some of them, have demonstration welds at the different power configurations which are really interesting

        • roterabe@discuss.tchncs.deOP
          link
          fedilink
          English
          arrow-up
          2
          ·
          edit-2
          1 year ago

          Could you send it over? Seems good to check it out. I’ll be on the lookout for a more powerful transformer in the meantime. I also went out and bought a more reputable SSR still rated at 40 amps.

    • glibg10b@lemmy.ml
      link
      fedilink
      English
      arrow-up
      1
      ·
      1 year ago

      I would worry about it when you’re talking about doubling your power draw

      *current draw. That would be four times the power (I2R)

      • jetA
        link
        fedilink
        English
        arrow-up
        1
        ·
        1 year ago

        P⁰ =i*V⁰

        V’ = 2*V⁰

        P’ = i * V’

        P’ = i * 2V⁰

        P’ =2 ( i * V⁰)

        P’ = 2 P⁰